ext_97979 (
thedan.livejournal.com
) wrote
in
cnoocy
2007-09-19 08:59 pm (UTC)
no subject
Started with:
(a^2)b+c = (d^2)(b+c)
rearranged to:
(a^2-d^2)(b+c) = c(a^2-1)
Decided c = 1 would make life easier:
(a^2-d^2)(b+1) = (a^2-1)
Wanted to make the leftmost factor simpler, so I set a = d+2 (based on your example):
(4d+4)(b+1) = d^2+4d+3
4(d+1)(b+1) = (d+1)(d+3)
4(b+1) = d+3
4b+1 = d
And we already know a in terms of d. There's probably a more general relationship I missed by making the assumptions c = 1 and a = d+2, but this is not the math I'm being paid to do. :)
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no subject
(a^2)b+c = (d^2)(b+c)
rearranged to:
(a^2-d^2)(b+c) = c(a^2-1)
Decided c = 1 would make life easier:
(a^2-d^2)(b+1) = (a^2-1)
Wanted to make the leftmost factor simpler, so I set a = d+2 (based on your example):
(4d+4)(b+1) = d^2+4d+3
4(d+1)(b+1) = (d+1)(d+3)
4(b+1) = d+3
4b+1 = d
And we already know a in terms of d. There's probably a more general relationship I missed by making the assumptions c = 1 and a = d+2, but this is not the math I'm being paid to do. :)